Lists: Conceptual Solutions

LIST COMPREHENSIONS AND LIST SLICING

Write out the list each list comprehension creates. 

lst = [1, 2, 3, 4, 5, 6, 7, 8] 
[x + 1 for x in lst]

[2, 3, 4, 5, 6, 7, 8, 9]

[x // 2 for x in lst if x % 2 == 0]

[1, 2, 3, 4]

[[y + 1 for y in range(x)] for x in lst if x < 4]

[[1], [1, 2], [1, 2, 3]]

Write out each sliced list. 

lst = [1, 2, 3, 4, 5, 6, 7, 8] 
lst[0 : 4]

[1, 2, 3, 4]

lst[: 8 : 2]

[1, 3, 5, 7]

lst[1 : -2 : -1]

[6, 5, 4, 3, 2, 1]

LIST FUNCTIONS

Draw out lst1 and lst2 each step of the way. 

lst1 = [1, 2, 3, 4] 
lst2 = [5, 6, 7, 8] 
lst2.append(lst1.pop())
lists_step1.png 
lst1.extend([9, 10])
 lst2.append([11, 12])
lists_step2.png 
lst1.pop(lst2[lst2[0] - 1]) 
lst2.remove(lst1[0] + 4)
lists_step3.png

code writing

Write a function that will take in a number n and create a list of all multiples of 3 from 0 to n inclusive. Assume n will always be >= 0.
def n_list(n):
>>> n_list(3)
[0, 3]
>>> n_list(6)
[0, 3, 6]
    return [x for x in range(n + 1) if x % 3 == 0]